12th Chemistry 1 Marks Organic nitrogen compounds
One Mark Study Material Unit wise as per reduced syllabus (2021-22)
TN 12th Chemistry 1 Marks Organic nitrogen compounds: 12th Chemistry Important Questions Chapter 13. +2 Chemistry Important 2 Marks, 3 Marks, 5 Marks Questions Based on reduced Syllabus 2021-2022. 12th Free Online Test (MCQs). HSC 12th Chemistry Revision Test Important Questions. 12th Tamil Full Guide.
Organic nitrogen compounds:
- 1. The aqueous solution sodium acetate, ammonium chloride, sodium nitrate are respectively basic, acidic, basic
- 2. Two molecules of propane nitrile in the presence of Na/ether to form 3-imino2- methypentanenitrile. The reaction is known as Thorpe nitrile condensation
- 3. Nef Carbonyl synthesis given by C6H5CHO (Benz aldehyde)
- 4. H2SO5 is Caro’s acid.
- 5. The major product of the reaction between m-dinitrobenzene with (NH4)S8 is
- 6. CH3Cl + KCN → A + H+/H2O → B + NH3 → C + Heating → D . The product “D” of the reaction is ? CH3CONH2(Acetamide)
- 7. CH3COCl (X) + NH3 → C4H9ON + Br2/KOH →CH3-CH2-CH2-NH2 identify X in the sequence of reaction. CH3-CH2-CH2-COCl
- 8. Ammonium salt of benzoic acid is heated strongly with P2O5 and the product so formed is reduced and then treated with NaNO2/ Hcl at low temperature. The final compound formed is Benzyl alcohol
- 9. Identify X in the sequence given below C6H4(NH2)(Cl) + CHCl3 + KOH →Y + HCl / 300K → X + methanoic acid. What is X? C6H4NH2Cl
- 10. The major product of the following reaction. C6H4 (COOH)2 + NH3 + strong heating →
- 11. Nitrobenzene on reaction with fuming nitric acid at 80-100oc forms 1,3, – dinitrobenzene products is formed.
- 12. Secondary nitro alkanes react with nitrous acid to form blue solution
- 13. C5H13N reacts with HNO2 to give optically active compound. The compound is
pentane – 2-amine
- 14. Triethylamine does not undergo acetylation.
- 15 When aniline reacts with acetic anhydride the product formed is acetanilide
- 16. The order of basic strength for methyl substituted amines in aqueous solution is
N(CH3)2H > N(CH3)H2 > N(CH3)3 . NH3
- 17. Hoffmann hypobromamide reaction is appropriate for converting acetamide to methanamine.
- 18. Consider the nitration of benzene using mixed with Con.H2SO4 & HNO3. If a large amount of KHSO4 is added to the mixture, the rate of nitration will be Slower
- 19.CH3-CH2-CH2-Br + NaCN → CH3-CH2-CH2-CN + NaBr this reaction will be fastest in this reagent is N, N’ – dimethylformamide (DME)
- 20. The no. of. Structural isomers possible from the molecular formula C3H9N is 3
- 21. The electrolytic reduction of nitrobenzene in strongly acidic medium produces p- aminophenol
- 22. C6H5N2+X– is the most stable diazonium salt.
- 23. Acetamide is treated with NaOH / Br2 reagents separately these would yield methylamine.
- 24. Aryl amines react with nitrous acid to produce phenols these statements about primary amine is false.
- 25. Methyl isocyanides on reduction with LiALH4 yields a secondary amine.
- 26. Electrolytic reduction of nitrobenzene in weakly acidic medium gives aniline
- 27. Amides can be converted into amines by a reaction named after Hofmann
- 28. Write the IUPAC name of (CH3)3-C-CH2-NO2 is 1,2 – dimethyl – 1 – nitro propane
- 29. Write the IUPAC name of C6H5-CH2-CH2-NO2 is 2 – phenyl-1-nitroethane
- 30. Acidic nature of nitro alkanes correct order is CH3-NO2 > CH3-CH2-NO2 > (CH3)2CH- NO2
- 31. When benzene is heated at 330K with a nitrating mixture electrophilic substitution takes place to form nitrobenzene (oil of mirbane)
- 32.CH3-NO2 + 3Cl2 + NaOH→ CCl3NO2 (Chloropicrin) + 3HCl
- 33. Nitrobenzene does not undergo Friedel – craft’s reaction due to the strong deactivating nature of –NO2 group.
- 34. Write the IUPAC name of CH3-N-C2H5-CH(CH3)2 is N-ethyl – N – methyl propan- 2 – amine
- 35. Aryl halides do not undergo nucleophile substitution with anion is formed by phthalimide.
- 36. The reduction reaction in which Na / C2H5OH with aryl cyanides gives primary amines such reaction is called as “Mendius Reaction”
- 37. The order of the reactivity of alkyl halides with amines is RI . RBr > RCl.
- 38. The basicity of order of aliphatic amines is R3N > R2NH > R-NH2
- 39. Alkyl & Aryl secondary amines react with nitrous acid to give N – nitro so amine as yellow oily liquid which is insoluble in water. This reaction is known as Liebermann’s nitoso compound
- 40. When aniline is treated with CS2 S-biphenyl urea is formed which on boiling with strong Hcl, phenylisocyanate (phenyl mustard oil) is formed. Such reaction is called as Mustard oil- reaction
- 41. In case of substituted aniline, electron releasing group like –CH3, -OCH3, -NH2
increase the basic strength.
- 42. In case of substituted aniline electron withdrawing group like –No2, – X , -COOH
decrease the basic strength.
- 43. The relative basicity of amines follows in this order Alkyl amines > Aralkyl amines > Ammonia > N – aralkyl amines > aryl amines.
- 44. Aniline reacts with Br2/ H2O (or) Br2/CH3COOH gives 2,4,6, tribromo aniline(White precipitate)
- 45. In the aqueous solution the substituted ammonium cations get stabilized not only by electron releasing (+I) effect of the alkyl group but also by solvation with water molecules
- 46. When vapor of an alcohol and ammonia are passed, over Al2O3.W2O3 (or) SiO2 at 4000c, all types of amines are formed this method is called Sabatier – Mailhe method.
- 47. Aniline and other aryl amines are usually colorless but when exposed to air they
become coloured due to oxidation
- 48. Aniline cannot be prepared by this Gabriel phthalimide method because the aryl halides do not undergo nucleophile substitution with anion formed by phthalimide.
- 49. Amino groups can be directly converted into nitro group by using Caro’s acid, (or)
persulphuric acid(or) peroxytrifluro acetic acid as an oxidizing agent..
- 50. Aromatic tertiary amines reacts with nitrous acid at 273k to give p-nitroso N,N- dimethyl aniline.